练习题一
create database mydb
go
use mydb
create table student
(
--学号
sno varchar(3) not null primary key,
--姓名
sname varchar(4) not null,
--性别
ssex varchar(2) not null,
--出生年月
sbirthday datetime,
--所在班级
class varchar(5)
)
create table teacher
(
--教工编号
tno varchar(3) not null primary key,
--教工姓名
tname varchar(4) not null,
--教工性别
tsex varchar(2) not null,
--教工出生日期
tbirthday datetime,
--职称
prof varchar(6),
--所在部门
depart varchar(10)
)
create table course
(
--课程号
cno varchar(5) not null primary key,
--课程名称
cname varchar(10) not null,
--教工编号
tno varchar(3) references teacher(tno)
)
create table score
(
--学号
sno varchar(3) not null references student(sno),
--课程号
cno varchar(5) not null references course(cno),
--成绩
degree decimal(4,1)
)
insert into student
values('108','曾华','男','1977-09-01','95033')
insert into student
values('105','匡明','男','1975-10-02','95031')
insert into student
values('107','王丽','女','1976-01-23','95033')
insert into student
values('101','李军','男','1976-02-20','95033')
insert into student
values('109','王芳','女','1975-02-10','95031')
insert into student
values('103','陆君','男','1974-06-03','95031')
insert into teacher
values('804','李诚','男','1958-12-02','副教授','计算机系')
insert into teacher
values('856','张旭','男','1969-03-12','讲师','电子工程系')
insert into teacher
values('825','王萍','女','1972-05-05','助教','计算机系')
insert into teacher
values('831','刘冰','女','1958-08-14','助教','电子工程系')
insert into course
values('3-105','计算机导论','825')
insert into course
values('3-245','操作系统','804')
insert into course
values('6-166','数字电路','856')
insert into course
values('9-888','高等数学','831')
insert into score
values('103','3-245','86')
insert into score
values('105','3-245','75')
insert into score
values('109','3-245','68')
insert into score
values('103','3-105','92')
insert into score
values('105','3-105','88')
insert into score
values('109','3-105','76')
insert into score
values('101','3-105','64')
insert into score
values('107','3-105','91')
insert into score
values('108','3-105','78')
insert into score
values('101','6-166','85')
insert into score
values('107','6-166','79')
insert into score
values('108','6-166','81')
select * from student
select * from teacher
select * from course
select * from score
题
1、 查询Student表中的所有记录的Sname、Ssex和Class列。
2、 查询教师所有的单位即不重复的Depart列。
3、 查询Student表的所有记录。
4、 查询Score表中成绩在60到80之间的所有记录。
5、 查询Score表中成绩为85，86或88的记录。
6、 查询Student表中“95031”班或性别为“女”的同学记录。
7、 以Class降序查询Student表的所有记录。
8、 以Cno升序、Degree降序查询Score表的所有记录。
9、 查询“95031”班的学生人数。
10、查询Score表中的最高分的学生学号和课程号。
11、查询‘3-105’号课程的平均分。
12、查询Score表中至少有5名学生选修的并以3开头的课程的平均分数。
13、查询最低分大于70，最高分小于90的Sno列。
14、查询所有学生的Sname、Cno和Degree列。
15、查询所有学生的Sno、Cname和Degree列。
16、查询所有学生的Sname、Cname和Degree列。
17、查询“95033”班所选课程的平均分。
18、假设使用如下命令建立了一个grade表：
create table grade(low numeric(3,0),upp numeric(3),rank char(1));
insert into grade values(90,100,'A');
insert into grade values(80,89,'B');
insert into grade values(70,79,'C');
insert into grade values(60,69,'D');
insert into grade values(0,59,'E');
现查询所有同学的Sno、Cno和rank列。
19、查询选修“3-105”课程的成绩高于“109”号同学成绩的所有同学的记录。
20、查询score中选学一门以上课程的同学中分数为非最高分成绩的记录。
21、查询成绩高于学号为“109”、课程号为“3-105”的成绩的所有记录。
22、查询和学号为108的同学同年出生的所有学生的Sno、Sname和Sbirthday列。
23、查询“张旭“教师任课的学生成绩。
24、查询选修某课程的同学人数多于5人的教师姓名。
25、查询95033班和95031班全体学生的记录。
26、查询存在有85分以上成绩的课程Cno.
27、查询出“计算机系“教师所教课程的成绩表。
28、查询“计算机系”与“电子工程系“不同职称的教师的Tname和Prof。
29、查询选修编号为“3-105“课程且成绩至少高于选修编号为“3-245”的同学的Cno、Sno和Degree,并按Degree从高到低次序排序。
30、查询选修编号为“3-105”且成绩高于选修编号为“3-245”课程的同学的Cno、Sno和Degree.
31、查询所有教师和同学的name、sex和birthday.
32、查询所有“女”教师和“女”同学的name、sex和birthday.
33、查询成绩比该课程平均成绩低的同学的成绩表。
34、查询所有任课教师的Tname和Depart.
35 查询所有未讲课的教师的Tname和Depart.
36、查询至少有2名男生的班号。
37、查询Student表中不姓“王”的同学记录。
38、查询Student表中每个学生的姓名和年龄。
39、查询Student表中最大和最小的Sbirthday日期值。
40、以班号和年龄从大到小的顺序查询Student表中的全部记录。
41、查询“男”教师及其所上的课程。
42、查询最高分同学的Sno、Cno和Degree列。
43、查询和“李军”同性别的所有同学的Sname.
44、查询和“李军”同性别并同班的同学Sname.
45、查询所有选修“计算机导论”课程的“男”同学的成绩表
下面是参考答案：
SQL语句练习题参考答案
1.select sname,ssex,class from student;
2.
select distinct(depart) from teacher;
or
select distinct depart from teacher;
3.select * from student;
4.
select * from score where degree between 60 and 80;
or
select * from score where degree>=60 and degree<=80;
5.
select * from score where degree in (85,86,88);
or
select * from score where degree=85 or degree=86 or degree=88;
6.select * from student where class=95031 or ssex='女';
7.select * from student order by class desc;
8.
select * from score order by cno asc,degree desc;
or
select * from score order by cno,degree desc;
9.
select count(*) from student where class=95031;
or
select count(sno) from student where class=95031;
10. select Sno as '学号',cno as '课程号', degree as '最高分' from score where degree=(select max(degree) from score);
11. select avg(degree) from score where cno='3-105';
12.
select cno,avg(degree) from score where cno like '3%' group by cno having count(sno)>5;
or
select cno,avg(degree) from score where cno like '3%' group by cno having count(*)>5;
13.select sno from score group by sno having min(degree)>70 and max(degree)<90;
14.
select student.sname,score.cno,score.degree from student,score where student.sno=score.sno;
or
select sname,cno,degree from student,score where student.sno=score.sno;
or
select x.sname,y.cno,y.degree from student x,score y where x.sno=y.sno;
15.
Select score.sno,course.cname,score.degree from score,course where score.cno=course.cno;
or
select sno,cname,degree from score,course where score.cno=course.cno;
or
select x.sno,y.cname,x.degree from score x,course y where x.cno=y.cno;
16.
select student.sname,course.cname,score.degree from student,course,score where student.sno=score.sno and course.cno=score.cno;
or
select sname,cname,degree from student,course,score where student.sno=score.sno and course.cno=score.cno;
or
select x.sname,y.cname,z.degree from student x,course y,score z where x.sno=z.sno and y.cno=z.cno;
17.
select cno,avg(degree) from score,student where student.sno=score.sno and class=95033 group by cno;
or
select y.cno,avg(y.degree) from student x,score y where x.sno=y.sno and x.class=95033 group by y.cno;
18.select sno,cno,rank from score,grade where degree between low and upp [order by rank]; [ ]表示可有可无
19.
select * from score where cno='3-105' and degree>(select degree from score where sno='109' and cno='3-105');
or
select x.* from score x,score y where x.cno='3-105' and x.degree>y.degree and y.sno='109' and y.cno='3-105';
20.
分析：1.成绩非本科最高select * from score where degree not in (select max(degree) from score group by cno)
选学一门以上的学生成绩：select sno from score group by sno having count(*)>1;
2.查询成绩非本科最高并且选1门以上的学生的成绩:
select * from score where degree not in(select max(degree) from score group by cno) group by sno having count(*)>1;
or
select * from (select * from score where degree not in(select max(degree) from score group by cno)) as aa group by sno having count(*)>=2;
通用答案：
select sno from
( select * from score
where degree not in
(select max(degree) from score group by cno)) as aa
group by sno having count(*)>=2;
21.
select * from score where degree>(select degree from score where sno=109 and cno='3-105');
or
select x.* from score x,score y where x.degree>y.degree and y.sno=109 and y.cno='3-105';
22.
select sno,sname,sbirthday from student where year(sbirthday)=(select
year(sbirthday) from student where sno=108);
23.
select * from score where cno in(select cno from course where tno=(select tno from teacher where tname='张旭'));
or
select cno,sno,degree from score where cno=(select x.cno from course x,teacher y where x.tno=y.tno and y.tname='张旭');
24.
select tname from teacher where tno in (select x.tno from course x,score y where x.cno=y.cno and y.cno in (select cno from score group by cno having count(*)>5));
or
select tname from teacher where tno in(select tno from course where cno in(select cno from score group by cno having count(*)>5));
or
select tname from teacher where tno in(select x.tno from course x,score y where x.cno=y.cno group by x.tno having count(x.tno)>5);
25.
select * from student where class in ('95033','95031');
or
select * from student where class=95033 or class=95031;
26.select distinct cno from score where degree in (select degree from score where degree>85);
27.
select * from score where cno in (select cno from course where tno in (select tno from teacher where depart='计算机系'));
or
select * from score where cno in(select x.cno from course x,teacher y where y.tno=x.tno and y.depart='计算机系');
28.select tname,prof from teacher where depart='计算机系' and prof not in (select prof from teacher where depart='电子工程系');
29.
select * from score where cno='3-105' and degree>(select min(degree) from score where cno='3-245') order by degree desc;
or
select * from score where cno='3-105'and degree>any(select degree from score where cno='3-245') order by degree desc;
30.
select * from score where cno='3-105' and degree>(select max(degree) from score where cno='3-245');
or
select * from score where cno='3-105' and degree>all(select degree from score where cno='3-245');
31.
select sname as name,ssex as sex,sbirthday as birthday from student
union
select tname,tsex,tbirthday from teacher;
32.
select sname as name,ssex as sex,sbirthday as birthday from student where ssex='女'
union
select tname,tsex,tbirthday from teacher where tsex='女';
33.select * from score a where degree<(select avg(degree) from score b where a.cno=b.cno);
34. select tname,depart from teacher where tno in(select tno from course);
35. select tname,depart from teacher where tno not in (select tno from course);
36.select class from student where ssex='男' group by class having count(sno)>=2;
37. select * from student where sname not like '王%';
38.select sname as '姓名',2010-year(sbirthday) as '年龄' from student;
39.
select sbirthday from student where sbirthday in (select min(sbirthday) from student)
union
select sbirthday from student where sbirthday in (select max(sbirthday) from student);
or
select sbirthday from student where sbirthday=(select min(sbirthday) from student) or sbirthday=(select max(sbirthday) from student);
40.select * from student order by class desc,sbirthday;
41.
select cname,tname from course,teacher where course.tno=teacher.tno and tsex='男';
or
select course.cname,teacher.tname from course,teacher where course.tno=teacher.tno and tsex='男';
or
select cname,tname from course x,teacher y where x.tno=y.tno and y.tsex='男';
or
select x.tname,y.cname from teacher x,course y where x.tno=y.tno and x.tsex='男';
42. select * from score where degree in (select max(degree) from score);
43.select sname from student where ssex=(select ssex from student where sname='李军');
44. select sname from student where ssex=(select ssex from student where sname='李军') and class=(select class from student where sname='李军');
45.select * from score where sno in(select sno from student where ssex='男') and cno in(select cno from course where cname='计算机导论');
注意：20题的前两个答案在sql server 中不支持，在mysql中支持
如果题答案中有错误，请记得及时通知我让我纠正错误！
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